Question

If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Answer 1

To solve this problem you must apply the proccedure shown below:
1. You have the following functions given in the problem above:

`f(x)=x-6` and
`g(x)=x1/2(x+3)=x(x+3)/2`
2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:

`g(x)*f(x)=(x-6)*x(x+3)/2`
3. Applying the distributive property, you have:

`g(x)*f(x)=( x^(3) + 3x^2 - 6x^(2) -18x)/2`

`g(x)*f(x)=(x^(3) - 3x^(2) -18x)/2`
The answer is:
`</strong>g(x)*f(x)=(x^(3) - 3x^(2) -18x)/2<strong>`