Question

The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution

Answer 1

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3