Question

A 10.-newton force is required to hold a stretched spring 0.20 meter from its rest position. What is the potential energy stored in the stretched spring?

Answer 1

`F_(r)` = 10 N
x = 0.2 m


`F_(r)` = -Kx

-K =
`(10 N)/(0.2 m)`

K = -50
`(N)/(m)`