Question

Find the value of Log2 32=y

Answer 1

y=5

Explanation:

We are solving

`log_232=y`

The logarithm is basically asking us this question:

`2^y=32`

Or what power should I raise 2 to so that it will give me 32?

We know that
`2^5=32`

Therefore
`y=5`.

P.S: calculating logarithms is not an algorithmic process: you have to rely mostly on educated guesses to get your answers.