Question

copper (1) oxide Cu2O is reduced to metallic copper by heating in a stream of hydrogen gas. what mass of water is produced when 10.00 g of copper is formed?

Answer 1

Answer:
1.41 g of H₂O

Solution:
The equation for given reaction is as follow,

Cu₂O + H₂ → 2 Cu + H₂O

According to equation,

127 g (2 mole) Cu is produced along with = 18 g (1 mole) of H₂O
So,
10 g Cu produced will generate = X g of H₂O

Solving for X,
X = (18 g × 10 g) ÷ 127 g

X = 1.41 g of H₂O