Question

Find the magnitude and direction angle for the vector v = 3 cos 123°i + 3 sin 123°j.

A. 3√2, 57°
B. 3√2, 123°
C. 3, 57°
D. 3, 123°

Answer 1

The vector written in its generic form is given by:
v = lvl cos theta ° i + lvl without theta ° j
Where.
lvl: magnitude of the vector
theta: angle of the vector with respect to the x axis.
For this case we have the following vector:
v = 3 cos 123 ° i + 3 without 123 ° j
Where,
lvl = 3
theta = 123 °
Answer:
The magnitude and direction angle for the vector v is:
D. 3, 123 °