Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)

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asked Jun 5, 2019 71.8k views

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Rwyland · Answer 1 · 2019-06-11T22:26:28+0000

Standard equation: (x-h)^2 + (y-k)^2 = r^2

Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10

Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2

Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)

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