Question

Solve this using the quadratic formula. Show work

2x^2+7x−5=0

Answer 1

Multiply the numbers (2*2=4)

`=(-7+√(7^2-4\cdot \:2\left(-5\right)))/(2\cdot \:2)`

Apply the rule

`√(7^2+2\cdot \:4\cdot \:5)`

7^2 =49

`=√(49+2\cdot \:4\cdot \:5)`

Multiply

`√(49+40)`

Add

`√(89)`


`=(-7-√(89))/(4)`

Final solution:

`x=(-7+√(89))/(4),\:x=(-7-√(89))/(4)`