Question

Calculate the volume in liters of a ×4.3910−5/moll mercury(ii) iodide solution that contains 500.mg of mercury(ii) iodide hgi2 . round your answer to 3 significant digits.

Answer 1

To calculate the volume of the mercury(II) iodide solution in liters, convert the mass of the solute to moles and use the Molarity equation. The volume is approximately 25.1 L.

Step-by-step explanation:

To calculate the volume in liters of the mercury(II) iodide solution, we need to convert the mass of the solute (HgI2) to moles, using the molar mass of HgI2. Then, we can use the equation Molarity = moles of solute / volume of solution in liters to find the volume.

First, calculate the moles of HgI2:

Moles = mass / molar mass = 500 mg / (454.39 g/mol) = 1.101 x 10^-3 mol

Next, rearrange the equation to solve for volume:

Volume = moles of solute / Molarity = 1.101 x 10^-3 mol / (4.3910^-5 M) = 25.07 L

Rounding to three significant digits, the volume of the solution is approximately 25.1 L.

Answer 2

the molarity of the solution is 4.39 x 10⁻⁵ mol/L
molarity is the number of moles of solute in 1 L of solution
in this instance there are 4.39 x 10⁻⁵ mol of HgI₂ in 1 L solution
the mass of HgI₂ in 1 L - 4.39 x 10⁻⁵ mol x 454.4 g/mol = 19.9 mg
if 19.9 mg are in 1 L
then 500.0 mg are in - 500.0 mg / 19.9 mg/L = 25.1 L
therefore volume is 25.1 L