Question

I’m sure this is easy but i'm gonna ask anyway

Answer 1

No, it's always okay to ask if you don't understand a question. Anyway, for this problem, we just have to plug in the value for V to solve for P :


`P = 4V^{ (1)/(3)} \\ P = 4(125)^{ (1)/(3)}`

A number to the power of 1/3 is the same as taking a cube root.


`P = 4(125)^{ (1)/(3)} \\ P = 4(5) \\ P=20`

The perimeter of one face of the cube is 20m.