Question

How many pounds of hamburger worth $1.05 per pound must be mixed with 60 pounds of hamburger worth $0.90 per pound to produce hamburger worth $1.00 per pound? Which of the following systems represents the word problem if x = pounds of hamburger worth $1.05 per pound? x + y = 60 and 1.05x + 0.90(60) = 1.00y x + 60 = y and 1.05x + 1.00y = 0.90(60) x + 60 = y and 1.05x + 0.90(60) = 1.00y

Answer 1

`(x+60)=y` and
`1.05x+0.90(60)=1.00y`

Explanation:

Let

x-----> pounds of hamburger worth
`\$1.05` per pound

we know that

The equation that represent the situation is

`1.05x+0.90(60)=1.00(x+60)` ------> equation A

Let

`y=(x+60)` -----> equation B

substitute equation B in equation A

`1.05x+0.90(60)=1.00y`

Answer 2

You are adding x pounds of hamburger to an existing 60 pounds. You want the total price to be 1.00 per pound times the total number of pounds.

The appropriate choice is the last one:
x + 60 = y and 1.05x + 0.90(60) = 1.00y