Question

The acid dissociation constant for an acid dissolved in water is equal to the ____.

a. equilibrium constant
b. equilibrium constant times the concentration of water
c. equilibrium constant divided by the concentration of water
d. equilibrium constant times the equilibrium constant of water

Answer 1

equilibrium constant times the concentration of water. - 100% guaranteed correct

Answer 2

Answer:The correct answer is option b.

Step-by-step explanation:

`HA+H_2O\rightleftharpoons A^-+H_20^+`

The equilibrium constant expression is given as:

`K_(eq)=([A^-][H_3O^+])/([HA][H_2O])`

`K_a=K_(eq)* [H_2O]=([A^-][H_3O^+])/([HA])`

The acid dissociation constant is product of equilibrium constant and concentration of water.

Hence,from the given options the correct answer is option b.