Question

A cran uses an average force of 5200N to lift a steel beam 25m. How much work does the crane do on the steal beam.

Please help or explain how to do this anyone. Please and thank youu

Answer 1

The work done by a force is given by:

`W=Fd \cos \theta`
where
F is the magnitude of the force
d is the distance covered by the object

`\theta` is the angle between the direction of the force and the direction of motion

In our problem,
`F=5200 N`,
`d=25 m` and
`\theta=0` (because the force is parallel to the direction of motion), so the work done by the crane is

`W=(5200 N)(25 m)(\cos 0^(\circ))=1.3 \cdot 10^5 J`