Question

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 mc030-1.jpg N2 + 3I2 The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Answer 1

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?


0.0136

Answer 2

0.0135 moles of iodine will be formed.

Step-by-step explanation:

`2NI_3\rightarrow N_2+3I_2`

Moles of nitrogen triiodide =
`(3.58 g)/(394.71 g/mol)=0.0090 mol`

According to reaction 2 moles of nitrogen triiodide gives 3 moles of iodione gas.

Then 0.0090 mol of nitrogen triiodide will give:

`(3)/(2)* 0.0090 mol=0.0135 mol`

0.0135 moles of iodine will be formed.