Question

In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.

Answer 1

49

Explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49