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CosA/1-tanA +sinA/1-cotA=sinA+cosA​

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User Nahla
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1 Answer

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Explanation:

cosA/(1−tanA) + sinA/(1−cotA)

cosA/(1−tanA) × cosA/cosA + sinA/(1−cotA) × sinA/sinA

cos²A/(cosA−sinA) + sin²A/(sinA−cosA)

cos²A/(cosA−sinA) − sin²A/(cosA−sinA)

(cos²A−sin²A) / (cosA−sinA)

(cosA+sinA) (cosA−sinA) / (cosA−sinA)

cosA+sinA

answered
User Artyom Okun
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8.6k points

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