Question

Please help please and thank you

Answer 1

Explanation:

`\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta`