Question

If 18.7 ml of 0.01500 Maqueous HCl is required to titrate 15.00 ml of an aqueous solution of NaOH to

the equivalence point, what is the molarity of the NaOH solution?

Answer 1

The molarity of NaOH is 0.02 M.

Step-by-step explanation:

Given data:

Volume of HCl = 18.7 mL

Molarity of HCl = 0.01500 M

Volume of NaOH = 15.00 mL

Molarity of NaOH = ?

Solution:

M₁V₁ = M₂V₂

0.01500 M × 18.7 mL = M₂ × 15.00 mL

M₂ = 0.3 M.mL /15.00 mL

M₂ = 0.02 M

The molarity of NaOH is 0.02 M.