Please give me the answers to these questions. The questions are in the picture above. If you’re going to give me the answers show your work. Pls answer them fast, I don’t have …

Question

asked Oct 25, 2020 64.6k views

1 Answer

Steven Clontz · Answer 1 · 2020-10-29T21:41:41+0000

Answer:

1. D

2. A

3. C

Explanation:

1. Given

6-(1)/(2)z=(2)/(3)

Multiply the equation by 6:

$6\cdot 6-6\cdot (1)/(2)z=6\cdot(2)/(3)\\ \\36-3z=4$

Hence,

$-3z=4-36\\ \\-3z=-32\\ \\3z=32\\ \\x=(32)/(3)$

2. Given

(3y)/(2)+(ky)/(4)=6

Multiply the equation by 4:

$(3y)/(2)\cdot 4+(ky)/(4)\cdot 4=6\cdot 4\\ \\6y+ky=24$

Use distributive property:

$y(6+k)=24\\ \\y=(24)/(6+k)$

3. Given

3-(w+2)>4+2w

Open the brackets using distributive property:

$3-w-2>4+2w\\ \\1-w>4+2w$

Hence,

1-w>4+2w