Question

A 7.25-kg bowling ball is being swung horizontally in a clockwise direction (as viewed from above) at a constant speed in a circle of radius 1.85 m.1. Suppose the time it takes the ball to make one complete revolution is 2.75 s. What is the centripetal acceleration?

Answer 1

`a_c=9.66(m)/(s^2)`

Step-by-step explanation:

The centripetal acceleration is given by:

`a_c=(v^2)/(r)(1)`

Here v is the linear speed and r is the radius of the circular motion. v is defined as the distance traveled to make one revolution (
`2\pi r`) divided into the time takes to make one revolution, that is, the period (T).

`v=(2\pi r)/(T)(2)`

Replacing (2) in (1) and replacing the given values:

`a_c=(((2\pi r)/(T))^2)/(r)\\a_c=(4\pi^2 r)/(T^2)\\a_c=(4\pi^2 (1.85m))/((2.75s)^2)\\a_c=9.66(m)/(s^2)`