Question

A student is studying a population of 100 Daylilies by the roadside. The plants in this population are genetically variable. The variance in seed production in this population (population A) is 20. She then takes one plant and creates cuttings to make a genetically identical population and plants the identical population (B) next to population A. The variance in seed production in population B is 5. What is the broad sense heritability in seed production for the roadside population of Daylilies?

Answer 1

broad sense heritability = 0.75

Explanation:

Step 1: Variables

phenotypic variation (Vp)

genotype variation (Vg)

environment variation (Ve)

broad sense heritability (H)

Step 2: Formulas:

H = Vg / Vp

Vp = Vg + Ve

Vg = Vp - Ve

Step 3: Given data

Vp = 20

Ve = 5

Step 4: Computation

Vg = 20 - 5 = 15

H = 15 / 20

H = 0.75

Hope this helps!