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Evaluate the surface integral. Sxz dSS is the boundary of the region enclosed by the cylinder y2 + z2 = 36 and the planes x = 0 and x + y = 9

Evaluate the surface integral. Sxz dSS is the boundary of the region enclosed by the cylinder y2 + z2 = 36 and the planes x = 0 and x + y = 9
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Evaluate the surface integral. Sxz dSS is the boundary of the region enclosed by the cylinder y2 + z2 = 36 and the planes x = 0 and x + y = 9

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User Pach
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Answer:

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Explanation:

Explanation in the image

Evaluate the surface integral. Sxz dSS is the boundary of the region enclosed by the-example-1
Evaluate the surface integral. Sxz dSS is the boundary of the region enclosed by the-example-2
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User Urda
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