Question

During combustion, methane yields carbon dioxide and water. The unbalanced equation for this reaction is:CH4(g)+O2(g) → CO2(g)+ H2O(l)

What will the mole ratios for the balanced equation be? What coefficients are needed in order to balance the equation?

Answer 1

answer 1 : 2 : 1 : 2

Step-by-step explanation:

Answer 2

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2

Step-by-step explanation:

CH4(g)+O2(g) → CO2(g)+ H2O(l)

To balance a chemical equation, you must have the same mole of each element in both sides of the reaction (reactant side and product side)

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

2 C

8 H

8 O

In both side.

It takes 1 mole of methane to react with 2 mole of oxygen in order to produce 1 mol of dioxide and 2 mole of water.

Mole ratios for the balanced equation be:

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2 - We should compare each compound

1 mol methane → 2 mole of oxygen

2 mole of oxygen → 1 mol of methane

2 mole of oxygen → 1 mol of dioxide

1 mole of dioxide → 1 mol of Methane

2 mole of water → 2 mole of oxygen (the same as opposite)

1 mol methane → 2 mole of water

2 mol of water → 1 mol of methane