Question

"If 25.0 mL of urine has a mass of 25.725 g and contains 1.929 g of solute, what is the mass/mass percent concentration of solute in the urine sample

Answer 1

To solve this problem we will find the proportion in terms of the solution and solution. According to the data given, the amount of solute is 1,929g in a solution of 25,725g, therefore the mass / mass percentage would be:

`\% m/m = (g_(solute))/(g_(solution)) * 100`

Replacing,

`\% m/m = (1.929g)/(25.725g)*100`

`\% m/m = 7.499\%`

Therefore there is 7.499% of solute in the urine sample.