Question

A titration is carried out to determine the concentration of the acid in an old bottle of aqueous HCl whose label has become unreadable.What is the HCl concentration if 32.1mL of 0.250M NaOH is required to titrate a 30.0mL sample of the acid?

Answer 1

The concentration of HCl is - 0.2675 M

Step-by-step explanation:

At equivalence point ,

Moles of
`HCl` = Moles of NaOH

Considering :-

`Molarity_(HCl)* Volume_(HCl)=Molarity_(NaOH)* Volume_(NaOH)`

Given that:

`Molarity_(NaOH)=0.250\ M`

`Volume_(NaOH)=32.1\ mL`

`Volume_(HCl)=30.0\ mL`

`Molarity_(HCl)=?\ M`

So,

`Molarity_(HCl)* Volume_(HCl)=Molarity_(NaOH)* Volume_(NaOH)`

`Molarity_(HCl)* 30.0=0.250* 32.1`

`Molarity_(HCl)=(0.250* 32.1)/(30.0)=0.2675\ M`

The concentration of HCl is - 0.2675 M