A sample of neon gas at 1.20 atm compresses from 0.250 L to 0.125 L. If the temperature remains constant, what is the final pressure in atm?A. 0.600 atm B. 1.000 atm C. 1.20 atm…

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asked Nov 7, 2020 203k views

1 Answer

Rao Sahab · Answer 1 · 2020-11-13T20:05:13+0000

Answer:

D. 2.40 atm

Step-by-step explanation:

At constant temperature and number of moles, using Boyle's law

${P_1}* {V_1}={P_2}* {V_2}$

Given ,

V₁ = 0.250 L

V₂ = 0.125 L

P₁ = 1.20 atm

P₂ = ? atm

Using above equation as:

${P_1}* {V_1}={P_2}* {V_2}$

${1.20\ atm}* {0.250\ L}={P_2}* {0.125\ L}$

${P_2=\frac{{1.20}* {0.250}}{0.125}\ atm$

${P_2}=2.40 atm$

Answer:- D. 2.40 atm