Question

Complete the following function to create a deep-copy on the heap of the argv array. Set the result pointer to point to your array. The only library calls you may use are malloc and memcpy. You may not use strdup.

Answer 1

Following are the code in the C programming Language.

//define function

void duplicate(char*argv, char**result) {

//set and initialize the variable to 0

int c = 0;

//set and initialize the char type pointer variable

char** t = argv;

//set the while loop

while(t){

//increment by 1

c++;

//increment by 1

t++;

}

//set malloc function in the pointer variable

result= malloc(sizeof(char)*(c+1));

//set the for loop

for(int i = 0; i < c; i++) {

//set malloc function in the pointer

(*result)[i] = malloc(strlen(argv[i])+1);

//copy the character from memory

memcpy(argv[i], (*result)[i], strlen(argv[i])+1) ;

}

//initialize null in the pointer

(*result)[i] = NULL;

}

Step-by-step explanation:

In the following code, we define function "duplicate()" and pass two character type pointer arguments "*argv" and "**result" and inside the function.

• Set an integer type variable "c" and initialize to 0.
• Set character type pointer variable "t" and initialize the value of pointer variable "argv".
• Set the while loop and increment in the variable "c" and "t" by 1.
• Set the malloc function in the pointer variable "result".
• Set the for loop to copy the character from the memory.
• Finally, initialize the pointer variable "result" to NULL.