Question

The half-life of plutonium-239 is about 24,000 years. What percent of an initial sample will remain in 1,000 years? Round your answer to the nearest tenth. Do not include the percent sign in answer.

Answer 1

Answer:.

%(Nt/No) = 97.15

= 100(to the nearest tenth)

Explanation:

Given;

Half life of plutonium t₀.₅= 24000years

Using the decay constant formula

λ =ln(2)/t₀.₅

Where,

λ = decay constant

λ = ln(2)/24000 = 2.89E-5

Using the decay formula.

Nt = Noexp(-λt)

where,

t = time of decay

No = initial mass

Nt = mass at time t

Nt/No = exp(-2.89 * 1000 E-5)

Nt/No = 0.9715

%(Nt/No) = 97.15

= 100(to the nearest tenth)