Question

On a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. Ex: The A key above middle C key has a frequency of 440 Hz. Each subsequent key (black or white) has a frequency of 440 * rn, where n is the number of keys from that A key, and r is 2(1/12). Given an initial frequency, output that frequency and the next 3 higher key frequencies. If the input is 440, the output is: 440 493.883 523.251 554.365.Note: Include one statement to compute r = 2(1/12) using the pow function, then use r in the formula fn = f0 * rn. (You'll have three statements using that formula, different only in the value for n).

Answer 1

sample output

Enter f0 = 440

440.0,466.1637615180899, 493.8833012561241,

523.2511306011974, 554.3652619537443

Step-by-step explanation:

import math // math library

def RaiseToPower(): // RaiseToPower method

r = math.pow(2,1/12) //r = 2^(1/12)

f0 = float(input('Enter f0 : ')) //input from user

//a key has a frequency,sy f0

print(f0,end=' ') //Display statement

for n in range(1,5): //Iterate the loop up to the next 4 higher key Hz

n = f0 * math.pow(r,n) //calculate the fn value

print(fn,end=' ') //Display statement

RaiseToPower() //Call RaiseToPower method