asked 183k views
5 votes
In a certain species of rabbits, black coat color is dominant over brown coat color. What is the probability of producing a rabbit with brown coat color from two rabbits that are both heterozygous for black coat color?

1) 0%
2) 25%
3) 75%
4) 100%

asked
User Sschrass
by
9.1k points

2 Answers

5 votes

Answer:

25% is the correct answer

Step-by-step explanation:

Just took a summit test

answered
User Diehell
by
8.2k points
2 votes

Answer:

2) 25%

Step-by-step explanation:

Let the traits for the black coat color be = BB

Let the traits for the brown coat color be = bb

Let the traits for heterozygous black coat color be = Bb

Now; the question says what is the probability of producing a rabbit with brown coat color from two rabbits that are both heterozygous for black coat color.

This implies that if two rabbits that are both heterozygous for black coat color cross together;

i.e Bb × Bb ;

The offspring will be (BB, Bb, Bb, bb)

BB (rabbits with black coat color) = 1/4

Bb (rabbits that are heterozygous for black coat color) = 2/4

bb (rabbit with brown coat color) = 1/4

Lets focus on ''bb'' ;

bb = 1/4 × 100%

= 25%

answered
User Patmood
by
8.4k points
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