Question

E is the midpoint of AD F is the midpoint of BC
What can you conclude?
Reason?

Answer 1

ΔEAB ≅ΔFCD

Explanation:

As ABCD is a parallelogram opposite sides are equal s AE ≅CF ,also AB≅ DC . Both E and F bisect the opposite lines in equal halves.

The parallelogram has a property that its opposite angles are equal . Therefore ∠c≅∠a, ∠d≅∠b

Using the SAA≅SAA postulate we conclude that ΔEAB ≅ΔFCD