Question

Log14/3+log11/5-log22/15=log

Answer 1

s=0.0500826

Explanation:

adding 10 as their base

log14/3+log11/5-log22/15=log

swap the sides

10s= log14/3+log11/5-log22/15

divid both sides by 10

log10 14/30+log10 11/50-log10 22/150

s=0.0500826

Answer 2

log(7)

Explanation:

`\log{(14)/(3)}+\log{(11)/(5)}-\log{(22)/(15)}=\log{((14)/(3)\cdot(11)/(5))/((22)/(15))}=\log{(14\cdot 11)/(22)}\\\\=\log{7}`

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The applicable rules of logarithms are ...

• log(ab) = log(a) +log(b)
• log(a/b) = log(a) -log(b)