Question

Scalar multiplication, can somebody please help me out? I would greatly appreciate it !!!!

Answer 1

-6

Explanation:

To get the resulting matrix each element of the matrix is multiplied with 3.

Let's see what the resulting matrix will look like;

The order of the resulting matrix will be the same as the order of the original matrix.

The original matrix is of the order 2 by 2.

So the resulting matrix will also be of the same order.

To get the 1st row 1st column element of the resulting matrix we multiply the 1st row 1st column element of the original matrix by 3. To get the 1st row 2nd column element of the resulting matrix we multiply the 1st row 2nd column element of the original matrix by 3 and so on until all the four elements of the original matrix are multiplied by 3. This method always works when a matrix is multiplied by a constant.

`\left[\begin{array}{ccc}-2*3&7*3\\4*3&6*3\\\end{array}\right]`

`\left[\begin{array}{ccc}-6&21\\12&18\\\end{array}\right]`