Question

A student pushes a 10 kg box with a force of 30 N at an angle 45 degrees below the horizontal . The box experi 21.2 N of force against the motion. What is the acceleration of the box?

Answer 1

Acceleration =0

Step-by-step explanation:

There are two forces on the box in horizontal direction.

First one is horizontal component of 30N at 45°.

`F=(1)/(√(2) )*30=21.2`

Another one is given in opposite to direction of motion mean opposite to this force.

Which is = 2.22 N

Now we know F (net) =mass*acceleration(center of mass)

21.2-21.2 =10*acceleration

acceleration =0