Question

In ∆ABC, m∠ACB = 90°, m∠A = 40°,

CD (D ∈AB ) is a segment perpendicular to the side AB . Find m∠DBC and m∠BCD.

Answer 1

Explanation:

u get this diagram^

to find DBC

B+40+90=180

B=50°

to find BCD

CDB is 90° ( since perpendicular to AB)

so taking triangle BCD

90+50+c=180

c=40°