Question

If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of Fe(OH)2 would be formed?

A. 291.44 g Fe(OH)2
B. 507 g Fe(OH)2
C. 499.06 g Fe(OH)2
D. 359.48 g Fe(OH)2

Answer 1

359.48 g Fe(OH)2. I just took this test

Answer 2

Answer: 359.29g

Explanation: the options are not correct. See attachment for explanation.