Question

Please help me on how to solve this, I am confused thank you.

verify sin(180 °-θ)=sinθ

Answer 1

Explanation:

sin(a-b)=sina cos b-cos a sin b

sin 180°=0

cos 180°=-1

`sin(180-\theta)=sin 180 cos \theta-cos 180sin \theta \\=0* cos \theta-(-1)  sin \theta\\=sin \theta`