Question

Identify the vertex for
f(x)=4x^2-8x-4

Answer 1

Explanation:

You could complete the square to do this, or you could just evaluate the h coordinate using the simple formula

`h=-(b)/(2a)`

then find k by subbing that h value into the equation for x to find y which is the same as k. In our quadratic, a = 4, b = -8, and c = -4.

`h=(-(-8))/(2(4))=1`

Now sub that value into the quadratic to find y (k):

`4(1)^2-8(1)-4=4-8-4=-8`

The vertex of the quadratic is (1, -8)