In the function y= [x] -1, which values of the function are equivalent? A) f(–1) and f(–2) B) f(1) and f(0) C) f(–3) and f(–2.1) D) f(2) and f(1.9) ANSWER is C.

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asked Apr 1, 2020 77.3k views

2 Answers

Null · Answer 1 · 2020-04-05T06:16:42+0000

Answer:

Option C) f(–3) and f(–2.1)

Explanation:

We are given the following information in the question:

f(x) = y = [x] - 1

where [x] is the greatest integer function.

A) f(–1) and f(–2)

$f(-1) = [-1] - 1 = -1-1 = -2\\f(-2) = [-2] - 1 = -2-1 = -3$

The two functions are not equivalent.

B) f(1) and f(0)

$f(1) = [1] - 1 = 1-1 = 0\\f(0) = [0] - 1 = 0-1 = -1$

The two functions are not equivalent.

C) f(–3) and f(–2.1)

$f(-3) = [-3] - 1 = -3-1 = -4\\f(-2.1) = [-2.1] - 1 = -3-1 = -4$

The two functions are equivalent.

D) f(2) and f(1.9)

$f(2) = [2] - 1 = 2-1 = 1\\f(1.9) = [1.9] - 1 = 1-1 = 0$

The two functions are not equivalent.