Question

Ifthe amount of ice on the planet increased to the amount that was present during the last glacial maximum, how muchwould it cause global sea level to fall? If you do not remember the approximate size of this rise, the volume of additionalice is 51000000 km3 and the surface area of the world's ocean is 361,000,000 km;A. less than 10 centimetersB. 10 centimeters to 1 meterC. 1 meter to 10 metersD. 10 meters to 50 metersE. more than 50 meters

Answer 1

h = 12.95 m , The correct answer is D

Step-by-step explanation:

For this exercise we use the definition of density

ρ= m V

For the water

`\rho_(w)` = m /
`V_(w)`

For ice

`\rho_(i)` = m /
`V_(i)`

The tabulated water density is
`\rho_(w)` = 997 Kg / m³ average between temperatures, the density near the freezing point that is 1000 kg/m³ can also be used, let's use the latter; The density of ice is 916.8 kg / m³

The mass of the water that is frozen is equal to the mass of ice that is formed, therefore, we can clear the doughs in the two equals formulas

Water

m =
`\rho_(w)`
`V_(w)`

Ice

m =
`\rho_(i)`
`V_(w)`

`\rho_(w)` Vw =
`\rho_(i)`
`V_(i)`

Vw =
`\rho_(i)` /
`\rho_(w)`
`V_(i)`

Reduce to SI system

`V_(i)` = 5.1 107 km³ (10³m / 1 km)³ = 5.1 10¹⁶ m³

Let's calculate

`V_(w)` = 916.8 / 1000 5.1 10¹⁶

`V_(w)` = 4,676 10¹⁶ m³

It indicates the surface of the ocean, so it is volume

V = A h

Where A is the surface and h is the height

A = 3.61 109 km² (10³ m / 1km)² = 3.61 10¹⁵ m²

h = V / A

h = 4.676 10¹⁶ / 3.61 10¹⁵

h = 12.95 m

The correct answer is D