Question

Once an airplane has reached its cruising altitude, its computer shows the destination to be 3,400 miles away. If the plane is traveling at a rate of 500 miles per hour, write a linear function of the distance d (in mi) the plane is from its destination t hours after reaching cruising altitude.

Answer 1

Option D is correct

Explanation:

distance (in mi) the plane is from its destination t hours after reaching cruising altitude = d

Time (hours) = t

Rate/ velocity = 500 mi/hr

Linear equation is in the form

y = mx + c

= d = vt + c

At t = 0

d = c = 3400 miles

m = -v (because the distance reduce with time)

m = -500

d = -500t + 3400

d = 3400 - 500t

Answer 2

d = 3400 - 500t

Explanation:

distance (in mi) the plane is from its destination t hours after reaching cruising altitude = d

Time (hours) = t

Rate/ velocity = 500 mi/hr

Linear equation is in the form

y = mx + c

= d = vt + c

At t = 0

d = c = 3400 miles

m = -v (because the distance reduce with time)

m = -500

d = -500t + 3400

d = 3400 - 500t