Question

A 539 g ball strikes a wall at 14.4 m/s and

rebounds at 13.8 m/s. The ball is in contact
with the wall for 0.033 s.
What is the magnitude of the average force
acting on the ball during the collision?
Answer in units of N.

Answer 1

461 N

Step-by-step explanation:

Impulse = change in momentum

F Δt = m Δv

F (0.033 s) = (0.539 kg) (14.4 m/s − (-13.8 m/s))

F = 461 N