Answer:
Explanation:
Given that Student scores on exams given by a certain instruc-tor have mean 74 and standard deviation 14.
Group I X Group II Y
Sample mean 74 74
n 25 64
Std error (14/sqrtn) 2.8 1.75
a) P(X>80) =

b) P(Y>80) =

c) X-Y is Normal with mean = 0 and std deviation =

P(X-Y>2.2) =

d)
