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A ball of mass 24 g is attached to a cord of length 0.463 m and rotates in a vertical circle. What is the minimum speed the ball must have at the top of the circle so the cord does not become slack? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.

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User Marvel
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1 Answer

4 votes

Answer:2.13 m/s

Step-by-step explanation:

Given

mass of ball
m=24 gm

Length of cord
L=0.463 m

acceleration due to gravity
g=9.8 m/s^2

minimum velocity after which cord will slack


(mv^2)/(r)=mg


v=√(rg)


v=√(0.463* 9.8)


v=2.13 m/s

answered
User Truemedia
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8.8k points