Question

Enter the slope and y−intercept as decimals. The scatter plot with trend line below shows data comparing wind speed and wind chill. The trend line passes through (10, 9) and (35, 0). Enter an equation for the trend line.

The equation of the trend line is
y =---------x +----------

Answer 1

`y=-0.36x+12.6`

Explanation:

we know that

The formula to calculate the slope between two points is equal to

`m=(y2-y1)/(x2-x1)`

we have

(10, 9) and (35, 0)

substitute the values in the formula

`m=(0-9)/(35-10)`

`m=-(9)/(25)=-0.36`

The equation of the line in slope intercept form is equal to

`y=mx+b`

With the slope
`m=-0.36` and point (35,0) substitute in the equation and solve for b

`0=-0.36(35)+b`

`0=-12.6+b`

`b=12.6`

therefore

The equation of the line in slope intercept form is

`y=-0.36x+12.6`