Question

An Atwood machine is constructed using a hoop with spokes of negligible mass. The 2.5 kg mass of the pulley is concentrated on its rim, which is a distance 20.3 cm from the axle. The mass on the right is 1.33 kg and on the left is 1.78 kg. 3.7 m 2.5 kg 20.3 cm ω 1.78 kg 1.33 kg What is the magnitude of the linear acceleration of the hanging masses? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s 2 .

Answer 1

The magnitude of the linear acceleration of the hanging masses in an Atwood machine can be calculated using the formula: a = (m2 - m1)g / (m1 + m2). The given masses are 1.33 kg on the right and 1.78 kg on the left. Plugging in these values, the magnitude of the acceleration is 1.3816 m/s^2.

Step-by-step explanation:

In an Atwood machine, the magnitude of the linear acceleration of the hanging masses can be calculated using the formula:

a = (m2 - m1)g / (m1 + m2)

Where:

a is the magnitude of the linear acceleration

m1 is the mass on the left (1.78 kg)

m2 is the mass on the right (1.33 kg)

g is the acceleration due to gravity (9.8 m/s^2)

Plugging in the given values, we get:

a = (1.33 kg - 1.78 kg) * 9.8 m/s^2 / (1.78 kg + 1.33 kg)

a = -0.44 kg * 9.8 m/s^2 / 3.11 kg

a = -1.3816 m/s^2

Since the question asks for the magnitude of the acceleration, we take the absolute value:

a = 1.3816 m/s^2

Answer 2

Step-by-step explanation:

63 kg ice skater finishes her performance and crossed the finish line with a speed of 10.8 m/s