Question

What is the value of e^ln7 x1
7e
7x
7

Answer 1

7x

Explanation:

Assuming your expression is :

`e^(\ln 7x)`

Then we simplify as follows

`e^(\ln 7x)=e^(\ln x+\ln 7)` since
`\ln A+\ln B=\ln AB`

`\implies e^(\ln 7x)=e^(\ln x)* e^(\ln 7)` since
`a^(m+n)=a^m* a^n`

`\implies e^(\ln 7x)=x*7` since
`e^(\ln a)=a`

`\implies e^(\ln 7x)=7x`