Which of the following is equivalent to the complex number i^26?

Question

asked Apr 27, 2022 54.5k views

2 Answers

Zaggo · Answer 1 · 2022-05-02T03:14:57+0000

Answer:

i²⁶ = -1

Explanation:

You can solve this by realising that 26 is divisible by 2, but, but 26/2 is not. With that we get:

$i^(26)\\=(i^2)^(13)\\=-1^(13)\\=-1$