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The perimeter of a rectangle is 54 meter. The difference of the length and the width is 11 meters. Find the demensions of the rectangle. Can you please just show the equation thanks.

1 Answer

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Final answer:

To find the dimensions of the rectangle, set up a system of equations using the given information. Solve the system of equations using the substitution method. The dimensions of the rectangle are 19 meters by 8 meters.

Step-by-step explanation:

To find the dimensions of the rectangle, we'll start by assigning variables. Let L represent the length and W represent the width. Given that the difference between the length and width is 11 meters, we can set up the equation L - W = 11.

Additionally, we know that the perimeter of a rectangle is calculated as P = 2L + 2W. Since the perimeter is given as 54 meters, we can write the equation as 2L + 2W = 54.

1. Perimeter equation:

Perimeter = 2l + 2w = 54 meters

2. Difference equation:

l - w = 11 meters

Solving for l and w:

From equation 2, we can express l in terms of w: l = w + 11

Substitute this expression for l in equation 1:

2(w + 11) + 2w = 54

2w + 22 + 2w = 54

4w + 22 = 54

4w = 32

w = 8

Since l = w + 11, then:

l = 8 + 11 = 19

Therefore, the dimensions of the rectangle are 19 meters by 8 meters.

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User Ben Rhouma Zied
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