Question

A consumer organization estimates that 32% of the households in a particular community have one television set, 38% have two sets, and 16% have three or more sets. If two households are chosen at random, what is the probability that at least one has one or more television sets

Answer 1

If two households are chosen at random, the probability that at least one has one or more television sets is equal to 0.9804 or (98.04%)

Explanation:

• 32% of the households have one television set,

• 38% have two sets

• 16% have three or more sets

Then 100% - ( 32%+ 38% + 16% ) = 14% of households does not have any television set

the probability that both of the two randomly chosen households does not have any television set is 0.14×0.14 =0.0196

If two households are chosen at random, the probability that at least one has one or more television sets is equal to

1 - (the probability that both of the two randomly chosen households does not have any television set) = 1- 0.0196 = 0.9804 (98.04%)